What groups is a user part of

[jenglert]

Does anyone know an easy/quick method to tell which groups a user is part of?

[stk137]

I don't know of one in the UI.
I definitely like a way to manage groups a user is a member of rather than having to go to each group one at a time and add the user.

There is this
http://wiki.alfresco.com/wiki/JavaScript_API#People_API

Array getContainerGroups(ScriptNode person)
  Gets the groups that contain the specified authority.

which could be used in a template to create a custom view or something.

[rosemaryl]

This is kind of dumb, I'm sure I'm just not looking in the right places, but once I do a call to getContainerGroups(…) I get a list of objects of type authorityContainer ({http://www.alfresco.org/model/user/1.0}authorityContainer).  I've been looking for some documentation for this type, namely, its properties so that I can get a human-readable group name out of it.

Thanks in advance!
~Rosemary

[andy]

Hi

This is in userModel.xml

<model name="usr:usermodel" xmlns="http://www.alfresco.org/model/dictionary/1.0">   <description>Alfresco User Model</description>   <author>Alfresco</author>   <published>2005-08-16</published>   <version>0.1</version>   <imports>      <import uri="http://www.alfresco.org/model/dictionary/1.0" prefix="d"/>      <import uri="http://www.alfresco.org/model/system/1.0" prefix="sys"/>   </imports>      <namespaces>      <namespace uri="http://www.alfresco.org/model/user/1.0" prefix="usr"/>   </namespaces>   <constraints>     <constraint name="usr:userNameConstraint" type="org.alfresco.repo.dictionary.constraint.UserNameConstraint" />      <constraint name="usr:authorityNameConstraint" type="org.alfresco.repo.dictionary.constraint.AuthorityNameConstraint" />   </constraints>      <types>            <type name="usr:authority">        <title>Alfresco Authority Abstract Type</title>         <parent>sys:base</parent>      </type>            <type name="usr:user">         <title>Alfresco User Type</title>         <parent>usr:authority</parent>         <properties>         <!– The tokenisation set here is ignored - it is fixed for this type –>         <!– This is so you can not break person lookup –>            <property name="usr:username">               <type>d:text</type>            <constraints>                  <constraint ref="usr:userNameConstraint" />               </constraints>            </property>            <property name="usr:password">               <type>d:text</type>            </property>            <property name="usr:enabled">               <type>d:boolean</type>            </property>            <property name="usr:accountExpires">               <type>d:boolean</type>            </property>            <property name="usr:accountExpiryDate">               <type>d:datetime</type>            </property>            <property name="usr:credentialsExpire">               <type>d:boolean</type>            </property>            <property name="usr:credentialsExpiryDate">               <type>d:datetime</type>            </property>            <property name="usr:accountLocked">               <type>d:boolean</type>            </property>            <property name="usr:salt">               <type>d:text</type>            </property>         </properties>      </type>         <type name="usr:authorityContainer">         <title>Alfresco Authority Type</title>         <parent>usr:authority</parent>         <properties>         <!– The tokenisation set here is ignored - it is fixed for this type –>         <!– This is so you can not break group lookup –>            <property name="usr:authorityName">               <type>d:text</type>            <constraints>                  <constraint ref="usr:authorityNameConstraint" />               </constraints>            </property>            <property name="usr:members">               <type>d:text</type>               <multiple>true</multiple>               </property>         </properties>         <associations>            <child-association name="usr:member">               <source>                  <mandatory>false</mandatory>                  <many>true</many>               </source>               <target>                  <class>usr:authority</class>                  <mandatory>false</mandatory>                  <many>true</many>               </target>               <duplicate>false</duplicate>            </child-association>         </associations>      </type>     </types>      </model>‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Andy

[rosemaryl]

Thanks Andy. 
Using the method of trial-and-error, I managed to get the information I wanted using a webscript.

Here are the guts of it, if anyone wants it (of course there's an xml file to go with this, but it's pretty standard, takes the username as a parameter):
usergroups.get.js

/*Get User Groups Webscript Javascript file*/var person = people.getPerson(args["name"]);model.groups = people.getContainerGroups(person);model.test = new Array();var containerGroups = people.getContainerGroups(person);for(var i=0;i<containerGroups.length;i++){   model.test = containerGroups[i].getQnamePath();}model.personName = person;‍‍‍‍‍‍‍‍‍‍‍‍

usergroups.get.html.ftl

<img src="/alfresco/images/logo/AlfrescoLogo32.png" alt="Alfresco" style="padding-right: 10px;"/><span class="mainTitle">User Groups</span><div style="margin-top: 10px;">   User ${personName.properties.userName} (${personName.properties.firstName} ${personName.properties.lastName}) is part of the groups:    <ul>   <#list groups as group>      <li>         ${group.qnamePath}   </#list>   </ul></div>‍‍‍‍‍‍‍‍‍‍

[aniruddh]

I don't know of one in the UI.
I definitely like a way to manage groups a user is a member of rather than having to go to each group one at a time and add the user.

There is this
http://wiki.alfresco.com/wiki/JavaScript_API#People_API

Array getContainerGroups(ScriptNode person)
  Gets the groups that contain the specified authority.

which could be used in a template to create a custom view or something.

Is this possible using WebServices?