Space or Content Properties modification

[bensonfungjava]

Hi,

I would like to modify the space properties or space properties via Alfresco Web Services API.  Please help provide with sample code how to modify.


Thanks
Benson

[jpotts]

Go to http://ecmarchitect.com/alfresco-developer-series and read the custom content types tutorial.

The example modifies content objects but it works the same for spaces.

Jeff

[bensonfungjava]

Thanks Jeff.  Do you know how I can display the tree structure of a space?  Is there any sample code?


Please help


Thanks
Benson

[jpotts]

If you download the OpenCMIS Workbench from Apache Chemistry and fire it up, you can open and run the Print Descendants Tree example in the Groovy Console. The code prints a tree of all descendants, but you could add a check to test whether or not the content type of each child is a folder if you are looking for spaces only.

import org.apache.chemistry.opencmis.client.api.*

session.rootFolder.getDescendants(-1).each {
    printTree(it, 0)
}

def printTree(Tree tree, int depth) {
    for(i in 0..depth) { print "  " }

    println tree.item.name
    
    if(tree.children.size > 0) {
        tree.children.each {
            printTree(it, depth + 1)
        }
    }
}‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

If you've never run the workbench or worked with CMIS before, assuming you are on Alfresco 4, the service URL for the ATOM Pub binding is http://localhost:8080/alfresco/cmisatom. If you are on older versions of Alfresco, the URL is http://localhost:8080/alfresco/s/api/cmis.

Hope that helps,

Jeff

[bensonfungjava]

Hi Jeff,

Thanks for your patience.  However, I still don't get it unfortunately.

Actually, what I want to do is to make a statistics of the all the directory structure of each space.

For example,

Under Company Home folder, I have created a Patient Record folder.  Under Patient Record folder, there are lots of different folders for every patient.  As there is a lot of patient folder under Patient Record folder, I need to develop a program to generate a list of directory structure of each patient folder so that I can view what type of file are being stored in these folders.  The following is the program to try to generate a list of directory structure, however, it can only return the number of folders under Patient Record folder, but cannot display every folder name.


Thank you very much
Benson

package test;

import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.Iterator;
import java.util.Map;
import java.util.Set;

import org.alfresco.webservice.repository.QueryResult;
import org.alfresco.webservice.types.NamedValue;
import org.alfresco.webservice.types.Query;
import org.alfresco.webservice.types.ResultSet;
import org.alfresco.webservice.types.ResultSetRow;
import org.alfresco.webservice.types.Store;
import org.alfresco.webservice.util.AuthenticationUtils;
import org.alfresco.webservice.util.Constants;
import org.alfresco.webservice.util.ISO9075;
import org.alfresco.webservice.util.WebServiceFactory;
import org.apache.axis.utils.BeanPropertyDescriptor;


public class TestAlfresco {

   /**
    * @param args
    */
   public static final Store STORE = new Store(Constants.WORKSPACE_STORE,
         "SpacesStore");

   public static String getNodeUUID(String rootPath, String folderName) {
      String uuid = "";

      try {
         
         Query query = new Query(Constants.QUERY_LANG_LUCENE, "PATH:\"/"
               + rootPath + "/" + "cm:" + ISO9075.encode(folderName)
               + "/*\" AND TYPE:\"cm:folder\"");
         System.out.println(query.getStatement());
         QueryResult queryResult = null;

         queryResult = WebServiceFactory.getRepositoryService().query(STORE,
               query, false);

         ResultSet resultSet = queryResult.getResultSet();
         System.out.println("No. of rows=" + resultSet.getTotalRowCount());
         ResultSetRow[] rows = resultSet.getRows();
         if (rows.length > 0) {
            for(int j = 0 ; j < rows.length ; j++) {
               System.out.println(" UUID ID :" + rows[j].getNode().getId());
               uuid = rows[j].getNode().getId();
               String[] strs = rows[j].getNode().getAspects();
               System.out.println("type=" + rows[j].getNode().getType());
               for(int i = 0 ; i < strs.length ; i++) {
                  System.out.println("strs=" + strs);
               }
               NamedValue[] nvs = rows[j].getColumns();
               
               for(int i = 0 ; i < nvs.length ; i++) {
                  System.out.println(nvs.getName());               
               }
//               resultSet = null;
//               rows = null;
            }
         }
      } catch (Exception e) {
         e.printStackTrace();
      }

      return uuid;
   }

   public static void main(String[] args) {
      // TODO Auto-generated method stub
      FileOutputStream output = null;
      // WebServiceFactory.setEndpointAddress("http://10.24.0.241:8080/alfresco/api");
      WebServiceFactory.setEndpointAddress(args[0]);
      try {
         output = new FileOutputStream("exception.txt");
         AuthenticationUtils.startSession("admin", "admin");
         System.out.println("Session start");
         String rootUUID = TestAlfresco.getNodeUUID("app:company_home",
               args[1]);
         System.out.println("rootUUID=" + rootUUID);
         AuthenticationUtils.endSession();
         System.out.println("End of session.");
      } catch (Exception e) {
         PrintStream ps = new PrintStream(output);
         e.printStackTrace(ps);
         ps.flush();
      }
   }

}

[gangadharjwala]

Hi Jeff

Thank you for this code. Its working fine. But i am getting this folder tree on console. I want folder list like pop up. I want to delete specific version document. I have groovy script to delete specific version. But i want first i search a document in list means if i click on main folder,i will get all subfolders and documents and if i click speific document,i will get all versions of that document. So can you please help me how i will get folders and subfolders in list format.

Thank you