how to map the image in html file

[amitbhardwaj]

hi friends
I am new to alfresco and i am facing some difficulty in it that is.
I have used xsd and xsl to create a webform. I have captured data using the web form, which gave me an HTML and an xml output. While capturing data in the webform i selected the  image which is in root ,and click next every thing is ok but

I am unable to see the gif in the generated html.

my XSD file is
=================================
<?xml version="1.0"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
   xmlns:nf="http://www.alfresco.org/alfresco/nf"
   targetNamespace="http://www.alfresco.org/alfresco/nf"
   elementFormDefault="qualified">

   <!– defines the form for creating a navigation hierarchy –>
   <xs:element name="Template1">
      <xs:complexType>
         <xs:sequence>
            <xs:element name="Author" type="xs:normalizedString" />
            <xs:element name="Description" type="xs:string"/>
            <xs:element name="Image" type="xs:anyURI"/>
         </xs:sequence>
      </xs:complexType>
   </xs:element>
</xs:schema>






my xsl file is
====================
<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="1.0" xmlns:xhtml="http://www.w3.org/1999/xhtml"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   xmlns:nf="http://www.alfresco.org/alfresco/nf"
   xmlns:fn="http://www.w3.org/2005/02/xpath-functions" exclude-result-prefixes="xhtml">
   <xslutput method="html" encoding="UTF-8" indent="yes"
      doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN"
      doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd'/>

   <xslreserve-space elements="*"/>

   <xsl:template match="/">
      <table>
         <tr>
         <td>
                   <xsl:value-of select="/nf:Template1/nf:Author"/>
         </td>
         
          </tr>   
         <tr>
         <td colspan="2">
            <xsl:value-of select="/nf:Template1/nfescription" disable-output-escaping="yes"/>
         </td>
          </tr>
          <tr>
         <td>
                   <img alt="abc">
              <xsl:attribute name="src">
                   <xsl:value-of select="concat($alf:request_context_path,./container/header_image)"/>
                 </xsl:attribute>
            </img>

            </td>
          </tr>   
      </table>
   </xsl:template>
</xsl:stylesheet>



please help me
thanks in advance
amit

[jpfi]

Hi,
I'm not sure, but my first idea was that

<xsl:value-of select="concat($alf:request_context_path,./container/header_image)"/>
‍‍

should be

<xsl:value-of select="concat($alf:request_context_path,'./container/header_image')"/>
‍‍

./container/header_image needs some ''.
Cheers, Jan

[amitbhardwaj]

hi
thanks for your reply , but problem is not solved

[zaizi]

Initial thinking… there isn't a reference to the image attribute in your XSLT. I.e. a line that says "/nf:Template1/nf:Image".

Assuming the line should be something along the lines of

<xsl:value-of select="concat($alf:request_context_path,./nf:Template1/nf:Image)"/>‍

[amitbhardwaj]

thank you all for for your valuable reply , my problem is solved thanks both of u