BonjourJe suis en train d'essayer de créer un modèle afin de defini de nouveaux types dérivant du type content.Je me suis inspirée de l'exemple de la page http://wiki.alfresco.com/wiki/Data_Dictionary_GuideJ'arrive a recréer le modèle de l'exemple, mais je n'arrive pas a créer mes propre modèles.Ce qui de passe, c'est que alfresco démarre corectement mais que le nouveau type n'apparait pas.Voici mes différents fichiers situés en …alfresco-1.3.0tomcatsharedclassesalfrescoextensioncommercialModel.xml<?xml version="1.0" encoding="UTF-8"?>
<!– Definition of new Model –>
<!– The important part here is the name - Note: the use of the my: namespace
which is defined further on in the document –>
<model name="cial:commercialmodel" xmlns="http://www.alfresco.org/model/dictionary/1.0">
<!– Optional meta-data about the model –>
<description>Model Commercial</description>
<author>Elise JANVIER</author>
<version>1.0</version>
<!– Imports are required to allow references to definitions in other models –>
<imports>
<!– Import Alfresco Dictionary Definitions –>
<import uri="http://www.alfresco.org/model/dictionary/1.0" prefix="d"/>
<!– Import Alfresco Content Domain Model Definitions –>
<import uri="http://www.alfresco.org/model/content/1.0" prefix="cm"/>
</imports>
<!– Introduction of new namespaces defined by this model –>
<!– NOTE: The following namespace my.new.model should be changed to reflect your own namespace –>
<namespaces>
<namespace uri="cial.commercial.model" prefix="cial"/>
</namespaces>
<types>
<!– Definition of new Content Type: Standard Operating Procedure –>
<type name="cial:facture">
<title>Facture</title>
<parent>cm:content</parent>
<properties>
<property name="cial:consultant">
<type>d:text</type>
</property>
<property name="cial:client">
<type>d:text</type>
</property>
<property name="cial:projet">
<type>d:text</type>
</property>
</properties>
</type>
</types>
</model>
example-model-context.xml<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE beans PUBLIC '-//SPRING//DTD BEAN//EN' 'http://www.springframework.org/dtd/spring-beans.dtd'>
<beans>
<!– Registration of new models –>
<bean id="extension.dictionaryBootstrap" parent="dictionaryModelBootstrap" depends-on="dictionaryBootstrap">
<property name="models">
<list>
<value>alfresco/extension/commercialModel.xml</value>
<value>alfresco/extension/exampleModel.xml</value>
</list>
</property>
</bean>
</beans>
web-client-config-custom.xml<alfresco-config>
<!– Example of adding languages to the list in the login page –>
<config evaluator="string-compare" condition="Languages">
<languages>
<language locale="fr_FR">French</language>
</languages>
</config>
<!– The config below shows how to incorporate the example model–>
<!– into the web client, for this to work you will need to –>
<!– rename example-model-context.xml.sample to example-model-context.xml –>
<config evaluator="string-compare" condition="Content Wizards">
<content-types>
<type name="my:sop" />
<type name="cial:facture"/>
</content-types>
</config>
<config evaluator="node-type" condition="my:sop">
<property-sheet>
<show-property name="mimetype" display-label-id="content_type"
component-generator="MimeTypeSelectorGenerator" />
<show-property name="size" display-label-id="size"
converter="org.alfresco.faces.ByteSizeConverter"
show-in-edit-mode="false" />
<show-property name="my:publishedDate" />
<show-association name="my:signOff" />
<show-property name="my:authorisedBy" />
<show-property name="my:testType" />
<show-child-association name="my:processSteps" />
</property-sheet>
</config>
<config evaluator="node-type" condition="cial:facture">
<property-sheet>
<show-property name="cial:consultant" />
<show-property name="cial:client" />
<show-property name="cial:projet" />
</property-sheet>
</config>
</alfresco-config>
merci d'avance pour votre aide
