Searching for PATH children

[marcus]

I'm wanting to get all the children of a specific node, which after reading the docs seemed like it should be achievable by doing something like the following

Node node = new Node(someNodeRef);
String query = "PATH:\""+node.getPath()+"/*\"";
[code]

However, for some reason it only seems to work if I replace the full namespace URIs (eg "{http://www.alfresco.org/model/application/1.0}") with the shortened versions ("app:") in the path. 

This is with 1.4p.‍‍‍‍‍‍‍‍

[andy]

Hi

That is correct. It uses the XPATH prefix style.

Node node = new Node(someNodeRef);
String query = "PATH:\""+node.getPath().toPrefixString(resolver)+"/*\"";
‍‍‍‍

Will give the correct path (prefixes and encoding of non allowed characters in PATH/XPATH)

Regards

Andy

[marcus]

That makes sense, however node.getPath() returns a String value. Am I missing something here?

[kevinr]

The issue is the Node class you are using (the web-client Node wrapper) returns the String version of the Path. You want the underlying repository Path object. This code should work in the web-client:

NodeService nodeService = Repository.getServiceRegistry(FacesContext.getCurrentInstance()).getNodeService();
Node node = new Node(nodeRef);
String query = "PATH:\"" + nodeService.getPath(nodeRef).toPrefixString(resolver) + "/*\""; 
‍‍‍‍‍

Thanks,

Kevin

[marcus]

Funny, I stumbled on this just before I got a notify email . However, I can't figure out what Namespace resolver I should be using; not just for this instance, but in other cases too. Are there rules about what resolver to use where?

[kevinr]

use the ServiceRegistry to get the NamespaceService as that supports the resolver interface for Alfresco and custom models.

Thanks,

Kevin