How to? Web Form filename variable in xsd

[parrym]

Is there a way to get the filename created in step one of the wizard and use it as a variable in the xsd in step two? I would like to do something like this:

   <xs:include schemaLocation="/get_category_choices.jsp?portal="${get_filename}/>
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[scottf]

I'm not sure if this will help but I use the following in my XSL.

Use either

<xsl:value-of select="$alf:rendition_file_name"/>‍

or

<xsl:value-of select="$alf:file_name"/>‍

Also take a look here: http://www.benh.co.uk/alfresco/web-forms-xforms/referencing-an-xml-element-within-an-output-path/
Hope that helps.

[parrym]

Hi Scott,

Thank you for your reply.

<xsl:value-of select="$alf:rendition_file_name"/>
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Will definitely be useful for me in another project. Unfortunately for this project I need to access the filename before the xsl template file is accessed and preferably in the xsd file used in step two of the wizard. As far as I can tell I may have to create my own custom wizard but will search a bit more before I attempt that.

[scottf]

Hey,
Sorry I couldn't be more help.

I find it hard to get answers to questions on these forums, very disappointing most of the time.

Hope you find a workaround, maybe you could let us know if you manage to find a way.

Thanks.