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How to send zip file or ZipInputstream as a process varriable

rajutalisetty
Champ in-the-making
Champ in-the-making
Hi,

I have a requirement to send a zipfile or zipInputstream as process varriable while starting of my workflow.(startProcessInstanceByKey("process", variableMap))

I have created a variablemap and set a zip file as one of the value as object type, but its not working.. How can i achieve this?

can anyone help me? thanks a lot!

Raju..
2 REPLIES 2

rajutalisetty
Champ in-the-making
Champ in-the-making
Hi,

I have found a solution by creating a Serializable zip object , and able to parse this.

Thanks,
Raju.

jbarrez
Star Contributor
Star Contributor
Great you found a solution, but I'm not sure if storing zips as process variables is a good idea… they will take up quite some space in the database …that will have an impact on performance.
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