How to get the mime type of a file?

[sam69]

Hi,

I want to get the mime type of a file when I get a ResultSet from the WebService. I searched, but it's not in the columns of the row..

Here is my code :

QueryResult rootChildren = WebServiceFactory.getRepositoryService().queryChildren(refEspaceAlfresco);
    ResultSet rootChildrenResults = rootChildren.getResultSet();
    ResultSetRow[] rowsElementsDuLot = rootChildrenResults.getRows();
    ResultSetRow row = null;
    ResultSetRowNode rsNode = null;
    for (int i = 0; i < rowsElementsDuLot.length; i++)
    {
      row = rowsElementsDuLot[i];
      if (row.getNode().getType().equals(Constants.TYPE_CONTENT)) {
        [b]Here I want to get the mime type of the file… [/b]
      }
      
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Thanks in advance for your help !

Regards,
Samuel

[sam69]

Nobody can answer me ? Or show me a ressource for webservice help.
Because I the Alfresco Webservice wiki page don't help me a lot. And I found the class structure not intuitive
The Web services sample are great, but not very complete.

Thanks in advance

[sam69]

I manage to gess the mime type with the file extension, but it's not a really good way, if the mime type is stocked somewere..

[rwetherall]

Hi,

You want to look at the value of the content property returned in the query results.

On a normal content type node this is {http://www.alfresco.org/model/content/1.0}content.  Its value should look something like this …

 contentUrl=store://2006/4/26/16/a874f499-d539-11da-a07f-7f7271fd4b4e.bin|mimetype=text/plain|size=652|encoding=UTF-8
‍‍

As you can see it is a string made up of the content location URL, the encoding and mimetype.

Currently there is no helper in the client to extract this information for you ( perhaps you counld add it 😉 ) but you should be able to extract the mime type fairly easily.

Hope this helps,
Roy

[sam69]

Thanks for your answer ! I already saw the mime-type here, but I though there was a better way…
Anymay, I keep the file-type extraction with the file extension, because it's enough for me, but maybe later 😉

[darkhope]

Is there any solution to open a file with the proper software ? The .bin extension launchs a specific program which can't read the file.
I've thought to create a copy of the file and rename the .bin with the mimetype informations, but I would like to know if there is a faster way to do it ?