topic Re: Migrating alfresco : A namespace prefix is not registered for uri http://www.alfresco.org/model/rmcustom/1.0 in Alfresco Forum

Migrating alfresco : A namespace prefix is not registered for uri http://www.alfresco.org/model/rmcustom/1.0

oounoughi — Thu, 10 Aug 2017 15:13:25 GMT

Hi,To upgrade from 4.0.d to Community-201704 (5.2), I installed an new 4.0.d in new server and perform migration of contentstore and database, but when start my new alfresco server I have this error:catalina.outINFO: Server startup in 36126 ms2017-08-10 16:32:00,277 INFO [alfresco.util.OpenOfficeC

Re: Migrating alfresco : A namespace prefix is not registered for uri http://www.alfresco.org/model/rmcustom/1.0

angelborroy — Mon, 14 Aug 2017 13:14:56 GMT

Probably you missed to install some customisation. The one including a model with namespace http://www.alfresco.org/model/rmcustom/1.0 is the one Alfresco is missing.

Re: Migrating alfresco : A namespace prefix is not registered for uri http://www.alfresco.org/model/rmcustom/1.0

cesarista — Mon, 14 Aug 2017 16:22:59 GMT

Maybe it is not related, but if in your original setup you had installed the RM module, you need it in the migration plan of the new version. This applies to any custom content models that you used previously. Take into consideration that many content models may be part of third party addons or custom extensions. So if you are migrating, you need these content models in the new instance.

Regards.

--C.

Re: Migrating alfresco : A namespace prefix is not registered for uri http://www.alfresco.org/model/rmcustom/1.0

oounoughi — Wed, 16 Aug 2017 08:46:30 GMT

Hi, thank you for your replays

It was a model deployed dynamically an removed from share and I found the model (in contentstore) with this query :

select alf_content_url.content_url from alf_node     left join alf_qname on alf_node.type_qname_id = alf_qname.id     left join alf_node_properties on alf_node_properties.node_id = alf_node.id     join alf_content_data on alf_content_data.id = alf_node_properties.long_value     left join alf_content_url on alf_content_url.id = alf_content_data.content_url_id where     alf_qname.local_name = 'dictionaryModel'     and alf_content_url.content_url is not null