topic Re: How to get the noderef of the sites using sitename? in Alfresco Forum

How to get the noderef of the sites using sitename?

madhu_sudireddy — Tue, 30 Jul 2019 03:52:16 GMT

Is there any web url for this?

Re: How to get the noderef of the sites using sitename?

vidhipanchal — Tue, 30 Jul 2019 04:51:59 GMT

Hi,

You can use the 'SiteService' (Java API) to get noderef and other detalis of site by site's shortName as below:

SiteInfo site = serviceRegistry.getSiteService().getSite("test");
NodeRef siteNode = site.getNodeRef();

This Link provides more information to you about siteServices.

As well as you can use Javascript API for getting noderef of site

var site = siteService.getSite("jncasr");
var siteNodeRef = site.getNode().getNodeRef();

Regards,

Vidhi

ContCentric

Re: How to get the noderef of the sites using sitename?

atultalhar — Wed, 29 Jul 2020 03:40:22 GMT

serviceRegistry does not have "getSiteService()" methode.

can you please let me know exact way ?

Re: How to get the noderef of the sites using sitename?

abhinavmishra14 — Wed, 29 Jul 2020 07:57:59 GMT

ServiceRegistery does have proxy for SiteService.

https://github.com/Alfresco/alfresco-repository/blob/master/src/main/java/org/alfresco/service/ServiceRegistry.java#L411

Which version of ACS you are on?

You have option to inject siteService via spring bean as well. Example of a bean def:

<bean id="example.action" class="com.example.TestAction" parent="action-executer">
   <constructor-arg ref="SiteService" /> <!-- proxy SiteService -->
</bean>

or

<bean id="example.action" class="com.example.TestAction" parent="action-executer"> 
  <constructor-arg ref="siteService" /> 
</bean>

or

<bean id="example.action" class="com.example.TestAction" parent="action-executer">
   <property name="siteService" ref="SiteService" /> <!-- proxy SiteService -->
</bean>

or

<bean id="example.action" class="com.example.TestAction" parent="action-executer"> 
    <property name="siteService" ref="siteService" /> 
</bean>