topic Re: Deserialize list of Nodes in Alfresco Forum

Deserialize list of Nodes

dadamia — Wed, 23 May 2018 09:48:45 GMT

Dear FriendsI Get List of Nodes, then I can not deserialize json response, I get Errorcom.fasterxml.jackson.databind.JsonMappingException: No suitable constructor found for type [simple type, class com.alfresco.client.api.common.representation.ResultPaging<com.alfresco.client.api.core.model.repre

Re: Deserialize list of Nodes

jpotts — Thu, 24 May 2018 16:45:51 GMT

What is the scenario where you would be remotely calling the Alfresco API (in other words, running from a system other than Alfresco) and then wanting to deserialize JSON objects using classes that you should not have access to (ie, Alfresco's)?

If you are in a remote system you should be deserializing JSON responses into your own POJO's, not trying to reconstruct Alfresco's.

If you are calling the remote API from within Alfresco then you shouldn't be doing that either because you've got access to the native API.

Re: Deserialize list of Nodes

dadamia — Fri, 25 May 2018 05:48:09 GMT

Thank You Jeff

I solve this problem:

I am in a remote system and I create own POJO class - Entry.class, then I extract information

List<EnrtyDTo> entryDTos= new ArrayList<EnrtyDTo>();

ObjectMapper om = new ObjectMapper();

JsonNode jsonNodeRoot = om.readTree(apiOutput);
List<JsonNode> nodes = jsonNodeRoot.findValues("entry");
for (JsonNode node : nodes) {
EnrtyDto entryDTo = om.treeToValue(node, EnrtyDto.class);
entryDTos.add(entryDTo);
}

Thank All