topic Re: How do I know if the content is a folder or file? in Alfresco Archive

How do I know if the content is a folder or file?

balistic — Thu, 01 Nov 2007 17:40:04 GMT

Hi,I am trying the display the contents of a repository using web services in a portlet. I can list the contents by using WebServiceFactory.getRepositoryService().queryChildren(ref) method. However, how would I know if the content is a folder or file if the query doesn't return any children? If it's

Re: How do I know if the content is a folder or file?

balistic — Thu, 01 Nov 2007 18:42:24 GMT

I found my answer. getType method of a node solved my problem. In case, people who want to know, the following is a code snippet


Reference ref = new Reference(STORE, uuid, null);
QueryResult queryResult = WebServiceFactory.getRepositoryService().queryChildren(ref);
            ResultSet resultSet = queryResult.getResultSet();

ResultSetRow[] rows = resultSet.getRows();

if (rows != null) {
         for (int i=0; i<rows.length; i++) {
             System.out.println((rows[i].getNode().getType());
             System.out.println((rows[i].getNode().getId());
        }
} 
‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Thanks!

Re: How do I know if the content is a folder or file?

morpheus — Mon, 28 Jul 2008 12:36:16 GMT

I getType method of a node


Reference ref = new Reference(STORE, uuid, null);
QueryResult queryResult = WebServiceFactory.getRepositoryService().queryChildren(ref);
            ResultSet resultSet = queryResult.getResultSet();

ResultSetRow[] rows = resultSet.getRows();

if (rows != null) {
         for (int i=0; i<rows.length; i++) {
             System.out.println((rows[i].getNode().getType());
             System.out.println((rows[i].getNode().getId());
        }
} 
‍‍‍‍‍‍‍‍‍‍‍‍‍‍

in this queryresult , where is the the real content ? ,

 rows.getNode()‍

returns just another node object , but where is the actual file, i uploaded to alfresco, is it in that object ? where do i have to go an other way to get that ?

And exists an normal API documentation for all the web service methods, like an Jdoc documentation ?
sry to blind to read found the doc at: http://wiki.alfresco.com/wiki/Alfresco_JavaDoc

Re: How do I know if the content is a folder or file?

vsuarez — Wed, 30 Jul 2008 12:18:31 GMT

You must use the Content Service and its "read" method. This method returns a set of Content type objects, each of them with a "url" property. Then you can access to this URL (by using a java.net.URL connection) and get the binary data.

NOTE: you MUST append "?ticket=your_session_ticket" to the URL. If you need a example, let me know.

Regards
Victor

I getType method of a node
Reference ref = new Reference(STORE, uuid, null);
QueryResult queryResult = WebServiceFactory.getRepositoryService().queryChildren(ref);
            ResultSet resultSet = queryResult.getResultSet();

ResultSetRow[] rows = resultSet.getRows();

if (rows != null) {
         for (int i=0; i<rows.length; i++) {
             System.out.println((rows[i].getNode().getType());
             System.out.println((rows[i].getNode().getId());
        }
} 
‍‍‍‍‍‍‍‍‍‍‍‍‍‍
in this queryresult , where is the the real content ? ,
 rows.getNode()‍
returns just another node object , but where is the actual file, i uploaded to alfresco, is it in that object ? where do i have to go an other way to get that ?

And exists an normal API documentation for all the web service methods, like an Jdoc documentation ?
sry to blind to read found the doc at: http://wiki.alfresco.com/wiki/Alfresco_JavaDoc

Re: How do I know if the content is a folder or file?

morpheus — Thu, 31 Jul 2008 09:56:21 GMT

You must use the Content Service and its "read" method. This method returns a set of Content type objects, each of them with a "url" property. Then you can access to this URL (by using a java.net.URL connection) and get the binary data.

NOTE: you MUST append "?ticket=your_session_ticket" to the URL. If you need a example, let me know.

thx
i found another option
with the class ContentUtils, i can get the content "directly" via getContentas …
which one is better/more performant ?
yours via URL or mine with the ContentUtils ?

Re: How do I know if the content is a folder or file?

vsuarez — Thu, 31 Jul 2008 10:14:29 GMT

You must use the Content Service and its "read" method. This method returns a set of Content type objects, each of them with a "url" property. Then you can access to this URL (by using a java.net.URL connection) and get the binary data.

NOTE: you MUST append "?ticket=your_session_ticket" to the URL. If you need a example, let me know.
thx
i found another option
with the class ContentUtils, i can get the content "directly" via getContentas …
which one is better/more performant ?
yours via URL or mine with the ContentUtils ?

ContentUtils does exactly the same thing, so no way is more or less efficient.

Re: How do I know if the content is a folder or file?

morpheus — Tue, 05 Aug 2008 12:21:33 GMT

ContentUtils does exactly the same thing, so no way is more or less efficient.

ok i tested, get an File with ContentUtils but the streams i get from the method is empty !!!!
what could that be ?

Re: How do I know if the content is a folder or file?

vsuarez — Wed, 06 Aug 2008 12:15:06 GMT

ok i tested, get an File with ContentUtils but the streams i get from the method is empty !!!!
what could that be ?

Can you access the content by web interface?

Re: How do I know if the content is a folder or file?

morpheus — Tue, 12 Aug 2008 12:56:01 GMT

hm yes that was an failure by myself , there were nothing in that file , maybe i have overwritten the content somehow,

Now i´m getting the typical "unable to get Content as Inpustream"- Exception !
But , it´s wired because it went well 10 times before !

ok i got it , in my app i fired the ContentUtils on Spaces and thats the cause why this Exception is being thrown !