topic Re: Define invisible element in xsd, Possible?? in Alfresco Archive

Define invisible element in xsd, Possible??

xexiz — Thu, 24 Jan 2008 13:35:05 GMT

Hello, here's what I am trying to do.. tell me if it's possible and how it is plz I would like to add an element in my xsd schema that won't appear in the XForms, like adding a node "CreationDate" which will contain the date when you create this xml. but I dont want this to be visible in the Alfre

Re: Define invisible element in xsd, Possible??

pmonks — Fri, 25 Jan 2008 04:39:14 GMT

It's not quite what you're after, but you can easily define a read-only field by adding the "fixed" facet to any element in your XML schema. This doesn't visually remove the field from the web form, but does make it non-editable.

It's also possible to define a custom XForms widget that generates an <input type="hidden"> HTML form field, although unfortunately the field still takes up some vertical whitespace within the web form (which can be mitigated somewhat if you put all of the hidden fields at the end of your schema). Details on the custom XForms widget functionality are at http://wiki.alfresco.com/wiki/Forms_Developer_Guide#Configuring_UI_control_mappings_in_web-client-config-wcm.xml . For a hidden widget I'd suggest inheriting the existing TextField widget and simply changing the type of field that's generated (from "text" to "hidden").

Re: Define invisible element in xsd, Possible??

pmonks — Fri, 25 Jan 2008 04:41:03 GMT

Oh and to embed today's date within the schema you'd use a dynamic include (see http://wiki.alfresco.com/wiki/Forms_Developer_Guide#Using_dynamic_types_in_schemas).

Re: Define invisible element in xsd, Possible??

xexiz — Fri, 25 Jan 2008 13:18:36 GMT

Yay! thanks for the complete answer! I'll give it a try today and give some news on my progress!!

thanks a lot!!

Re: Define invisible element in xsd, Possible??

xexiz — Fri, 25 Jan 2008 14:53:52 GMT

Well for now I'm already stuck.. there is a stupid error making no sense at all.. the JSP wont do what i want for now (adding a hidden form field with today's date as default value) but well at least i'm not having error when "Preview File" in my sandbox on the jsp.

By the way, if i remove both red lines the xsd work well 😉 only if im trying to include the jsp that generate this error

im simply trying to make my include work first and here's the error i'm having

org.alfresco.web.forms.FormProcessor$ProcessingException: org.alfresco.web.forms.xforms.FormBuilderException: errors parsing schema: at line 37 column 5: The element type "hr" must be terminated by the matching end-tag "". at line -1 column -1: The element type "hr" must be terminated by the matching end-tag "".

XSD

<?xml version="1.0" encoding="utf-8"?>
<xs:schema xmlns:alf="http://www.alfresco.org" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
    <xs:include schemaLocation="/getCreationDate.jsp"/>
<xs:element name="News">
    <xs:complexType>
      <xs:sequence>
        <xs:element minOccurs="1" maxOccurs="2" name="Content">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="Title" type="xs:normalizedString" />
              <xs:element name="Body" type="xs:string" />
            </xs:sequence>
            <xs:attribute name="lang">
              <xs:simpleType>
                <xs:restriction base="xs:normalizedString">
                  <xs:enumeration value="en">
                    <xs:annotation>
                      <xs:appinfo>
                        <alf:label xmlns:alf="http://www.alfresco.org">English</alf:label>
                      </xs:appinfo>
                    </xs:annotation>
                  </xs:enumeration>
                  <xs:enumeration value="fr">
                    <xs:annotation>
                      <xs:appinfo>
                        <alf:label xmlns:alf="http://www.alfresco.org">FranÃƒÂ§ais</alf:label>
                      </xs:appinfo>
                    </xs:annotation>
                  </xs:enumeration>
                </xs:restriction>
              </xs:simpleType>
            </xs:attribute>
          </xs:complexType>
        </xs:element>
        <xs:element name="Type">
          <xs:simpleType>
            <xs:restriction base="xs:normalizedString">
              <xs:enumeration value="Financial Results" />
              <xs:enumeration value="Internal Communications" />
            </xs:restriction>
          </xs:simpleType>
        </xs:element>
        <xs:element name="PublishingDate" type="xs:date" />
        <xs:element name="CreationDate" type="creation_date"/>
        <xs:element name="NbForIndex" type="xs:integer">
          <xs:annotation>
            <xs:appinfo>
              <alf:label xmlns:alf="http://www.alfresco.org">How much will appear on index?</alf:label>
            </xs:appinfo>
          </xs:annotation>
        </xs:element>
      </xs:sequence>
    </xs:complexType>
</xs:element>
</xs:schema>

JSP

<jsp:root version="1.2" xmlns:jsp="http://java.sun.com/JSP/Page" xmlns:c="http://java.sun.com/jsp/jstl/core">
<jsp:directive.page language="java" contentType="text/html; charset=UTF-8" isELIgnored="false"/>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:alf="http://www.alfresco.org/alfresco" elementFormDefault="qualified">
   <xs:simpleType name="creation_date">
      <xs:restriction base="xs:normalizedString">
         <jsp:element name="xs:normalizedString">
            <jsp:attribute name="value"><c:out value="2008-01-25"/></jsp:attribute>
            <jsp:body>
               <xs:annotation>
                  <xs:appinfo>
                     <alf:label><c:out value="CreationDate"/></alf:label>
                  </xs:appinfo>
               </xs:annotation>
            </jsp:body>
         </jsp:element>
      </xs:restriction>
   </xs:simpleType>
</xs:schema> 
</jsp:root>‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Re: Define invisible element in xsd, Possible??

pmonks — Fri, 25 Jan 2008 18:33:28 GMT

For starters the MIME type (content type) returned by the JSP is wrong - the MIME type for XML Schema is "text/xml".

The error message suggests that the XML Schema fragment generated by the JSP is not valid, so in addition to fixing the MIME type it would also be worth previewing the JSP directly (via the "preview" icon in the Alfresco web client) and validating the output with an XML validation tool.

Re: Define invisible element in xsd, Possible??

xexiz — Fri, 25 Jan 2008 18:42:59 GMT

ok, the error is now

org.alfresco.web.forms.FormProcessor$ProcessingException: org.alfresco.web.forms.xforms.FormBuilderException: error parsing schema: at line 45 column 63: src-resolve: Cannot resolve the name 'creation_date' to a(n) 'type definition' component.‍

so i guess then my JSP isnt right! even if I've type <xs:simpleType name="creation_date">

Re: Define invisible element in xsd, Possible??

pmonks — Fri, 25 Jan 2008 18:46:26 GMT

Did you validate the output from the JSP in an XML validation tool (XML Spy, oXygen, etc.)?

Re: Define invisible element in xsd, Possible??

xexiz — Fri, 25 Jan 2008 18:56:56 GMT

the JSP seems to generate this source:

<?xml version="1.0" encoding="utf-8" ?>
<xs:schema xmlns:alf="http://www.alfresco.org/alfresco" xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified">
   <xs:simpleType name="creation_date">
      <xs:restriction base="xs:normalizedString">
         <xs:normalizedString value="2008-01-25">
            <xs:annotation>
               <xs:appinfo>
                  <alf:label>CreationDate</alf:label>
               </xs:appinfo>
            </xs:annotation>
         </xs:normalizedString>
      </xs:restriction>
   </xs:simpleType>
</xs:schema>‍‍‍‍‍‍‍‍‍‍‍‍‍‍

which is unvalid "The 'http://www.w3.org/2001'XMLSchema:normalizedString' element is not supported in this context.

but the fact is I really dont know what to put in the jsp so it could include the today's date! I pick something from the forum and try to modify it but I've never write a JSP which would define a schema type.. so i'm kinda lost…

Re: Define invisible element in xsd, Possible??

pmonks — Fri, 25 Jan 2008 20:44:17 GMT

Generating XML Schema from a JSP is not really any different from generating anything else from a JSP, except that XML Schema has a strict format that must be adhered to. A good introduction to XML Schema is at: http://www.w3schools.com/schema/default.asp.

An XML tool with strong XML Schema support can help too - you might start by constructing the schema by hand in the tool, for example, then paste that into the JSP to get the dynamic include working, then finally replace hardcoded portions of the schema with JSP logic.

Re: Define invisible element in xsd, Possible??

xexiz — Mon, 28 Jan 2008 14:54:09 GMT

Yeah! Finally, no more error, but the element I'm including by the JSP does not apear in the final generated XML

JSP:

<?xml version="1.0" encoding="utf-8" ?>
<xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element default="2008-01-25" name="creationDate" type="xs:date" />
</xs:schema>‍‍‍‍

XML result:


<News>
<Content lang="en">
<Title>d</Title>
<Body>d</Body>
</Content>
<Type>Financial Results</Type>
<PublishingDate>2008-01-08</PublishingDate>
<NbForIndex>2</NbForIndex>
</News>‍‍‍‍‍‍‍‍‍‍

XSD:

<?xml version="1.0" encoding="utf-8" ?>
<!– Created with Liquid XML Studio 1.0.7.0 (http://www.liquid-technologies.com) –>
<xs:schema xmlns:alf="http://www.alfresco.org" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:include schemaLocation="/getCreationDate.jsp" />
  <xs:element name="News">
    <xs:complexType>
      <xs:sequence>
        <xs:element minOccurs="1" maxOccurs="2" name="Content">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="Title" type="xs:normalizedString" />
              <xs:element name="Body" type="xs:string" />
            </xs:sequence>
            <xs:attribute name="lang">
              <xs:simpleType>
                <xs:restriction base="xs:normalizedString">
                  <xs:enumeration value="en">
                    <xs:annotation>
                      <xs:appinfo>
                        <alf:label xmlns:alf="http://www.alfresco.org">English</alf:label>
                      </xs:appinfo>
                    </xs:annotation>
                  </xs:enumeration>
                  <xs:enumeration value="fr">
                    <xs:annotation>
                      <xs:appinfo>
                        <alf:label xmlns:alf="http://www.alfresco.org">FranÃƒÂ§ais</alf:label>
                      </xs:appinfo>
                    </xs:annotation>
                  </xs:enumeration>
                </xs:restriction>
              </xs:simpleType>
            </xs:attribute>
          </xs:complexType>
        </xs:element>
        <xs:element name="Type">
          <xs:simpleType>
            <xs:restriction base="xs:normalizedString">
              <xs:enumeration value="Financial Results" />
              <xs:enumeration value="Internal Communications" />
            </xs:restriction>
          </xs:simpleType>
        </xs:element>
        <xs:element name="PublishingDate" type="xs:date" />
        <xs:element name="NbForIndex" type="xs:integer">
          <xs:annotation>
            <xs:appinfo>
              <alf:label xmlns:alf="http://www.alfresco.org">How much will appear on index?</alf:label>
            </xs:appinfo>
          </xs:annotation>
        </xs:element>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

EDIT 10h47AM:
What type the JSP should be anyways? because i'm trying to switch to this code and it's always interpret wrong when I try the "preview file" I've try to create it with XML. HTML, and Java Class type.. without success

it's always display this when I click preview file:
" name="" type="">

<jsp:root version="1.2" xmlns:jsp="http://java.sun.com/JSP/Page" xmlns:c="http://java.sun.com/jsp/jstl/core">
<jsp:directive.page language="java" contentType="text/html" isELIgnored="false"/>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:alf="http://www.alfresco.org/alfresco" elementFormDefault="qualified">
   <jsp:element name="xs:element">
      <jsp:attribute name="name"><c:out value="CreationDate"></c:out></jsp:attribute>
      <jsp:attribute name="type"><c:out value="xs:date" ></c:out></jsp:attribute>
      <jsp:attribute name="default"><c:out value="2008-01-24" ></c:out></jsp:attribute>
      <jsp:body>
         <xs:annotation>
            <xs:appinfo>
               <alf:label><c:out value="Creation Date"/></alf:label>
            </xs:appinfo>
         </xs:annotation>
      </jsp:body>
   </jsp:element>   
</xs:schema>
</jsp:root>‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

[img]http://img81.imageshack.us/img81/695/addjspma1.jpg[/img]

Re: Define invisible element in xsd, Possible??

kvc — Tue, 29 Jan 2008 14:04:22 GMT

If you preview via the virtualization server the included JSP from within your sandbox, you'll need see that the JSP is generating a valid schema output. Currently, sounds like from your earlier post this is what your JSP is generating:

<?xml version="1.0" encoding="utf-8" ?>
<xs:schema xmlns:alf="http://www.alfresco.org/alfresco" xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified">
   <xs:simpleType name="creation_date">
      <xs:restriction base="xs:normalizedString">
         <xs:normalizedString value="2008-01-25">
            <xs:annotation>
               <xs:appinfo>
                  <alf:label>CreationDate</alf:label>
               </xs:appinfo>
            </xs:annotation>
         </xs:normalizedString>
      </xs:restriction>
   </xs:simpleType>
</xs:schema>
‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

To make your schema valid, you'll need to generate the following:

<?xml version="1.0"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           elementFormDefault="qualified">
  <xs:simpleType name="creation_date">
    <xs:restriction base="xs:normalizedString">
      <xs:enumeration value="2008-01-25">
            <xs:annotation>
               <xs:appinfo>
                  <alf:label>CreationDate</alf:label>
               </xs:appinfo>
            </xs:annotation>
      </xs:enumeration>
    </xs:restriction>
  </xs:simpleType>
</xs:schema>
‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Try that … should help.

Kevin

Re: Define invisible element in xsd, Possible??

xexiz — Tue, 29 Jan 2008 14:26:28 GMT

Thanks Kevin!
Your example is working, but it's now printing an option field, my optimal goal is to be able to add the creation date into the generated xml without the user see it, I doubt I will be able to hide this option field.. with a text field I would be able, I think.. or at least made it disable if I really cant make it disapear..

thx, my form is progressing!