topic Alfresco CMIS Web Scripts API for 'getContent' by path is not working in Alfresco Archive

Alfresco CMIS Web Scripts API for 'getContent' by path is not working

mathias_lin — Fri, 08 Nov 2013 09:10:34 GMT

I had readhttp://forums.alfresco.com/forum/developer-discussions/alfresco-api/cmis-getcontent-example-09262012-1805but did not find an OpenCMIS services URI / sample of how to fetch node content by providing it's path only, not it's UUID.<strong>The problem:</strong>I have a file in my A

Re: Alfresco CMIS Web Scripts API for 'getContent' by path is not working

arnoldschrijve1 — Fri, 08 Nov 2013 10:04:36 GMT

Hi,

Seems like the root of your path is too high up the hierarchy. That's why you see company_home appear twice in your error message.
Try to remove the company_home part like such:

http://localhost:8081/alfresco/service/cmis/p/Data%20Dictionary/Cleaner%20Configs/cleaner.properties/content?a=false

Re: Alfresco CMIS Web Scripts API for 'getContent' by path is not working

arnoldschrijve1 — Fri, 08 Nov 2013 10:05:39 GMT

And use 8080 of course (I tested against my own alfresco repo on 8081

Re: Alfresco CMIS Web Scripts API for 'getContent' by path is not working

kaynezhang — Sun, 10 Nov 2013 02:39:47 GMT

Cmis's root / is mapped to /app:company_home,so /Data%20Dictionary is automaticlly mapped to /app:company_home/Data%20Dictionary.you should not prefix it with /app:company_home,or it'll be interpretered to /app:company_home/app:company_home/Data%20Dictionary which will be not found .
And using cmis you can only access nodes under /app:company_home.

Re: Alfresco CMIS Web Scripts API for 'getContent' by path is not working

spilby — Fri, 30 May 2014 10:57:00 GMT

How can I obtain a display path from the Alfresco API? (without qnames)

If I want the path of a node, I do the following:


getNodeService().getPath(nodeRef)
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It returns something like this:

<blockcode>
{http://www.alfresco.org/model/application/1.0}company_home/{http://www.alfresco.org/model/application/1.0}user_homes/{http://www.alfresco.org/model/content/1.0}AGP/{http://www.alfresco.org/model/content/1.0}AGP2/{http://www.alfresco.org/model/content/1.0}New_x0020_Documents/{http://www.alfresco.org/model/content/1.0}Test.pdf
</blockcode>

But I want a path like:

<blockcode>
/company_home/User Homes/AGP/AGP2/New Documents/Test.pdf
</blockcode>

Without the qnames, types, and with the correct format without _x0020_ codes.

Are there a method from the Alfresco API to get this type of path? Or I must decode it writing an own method in Java?

Thanks!

PD: I answer myself… )


getNodeService().getPath(nodeRef).toDisplayPath(getNodeService(), getPermissionService()
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