topic Extract dataObj values ??? in Alfresco Archive

Extract dataObj values ???

yascorp — Tue, 29 Apr 2014 13:48:05 GMT

Hello,I have done an ajax.request to send data to a specific urlhtml.ftl<javascript>function generateForm() {var title = new YAHOO.util.Element('${args.htmlid}-title');var title_v = title.get('value');var description = new YAHOO.util.Element('${args.htmlid}-description');var description_v = de

Re: Extract dataObj values ???

afaust — Tue, 29 Apr 2014 13:51:50 GMT

Hello,

for "json" to be defined you need to make sure you actually submit in JSON format and your web script is setup to handle JSON. That requires you to
<ul>
<li>set the JSON request content type - you can do that manually by setting the requestContentType parameter or instead use jsonRequest or even jsonPost (which allows you to omit the method)</li>
<li>state that your controller expects a JSON request by naming it xy.post.json.js</li>
</ul>

Also, when you submit as JSON, you do not need to manually stringify any data. YUI / Alfresco takes care of that.

Regards
Axel

Re: Extract dataObj values ???

yascorp — Tue, 29 Apr 2014 14:39:07 GMT

Thanks for your reply Axel !
I add the submitType like this :
<javascript>
……..
……..
……..
Alfresco.util.Ajax.request(
               {
                   url: Alfresco.constants.PROXY_URI + "api/form/add-news",
                   method: Alfresco.util.Ajax.POST,
                  dataObj:
                     {
                        site: Alfresco.constants.SITE,
                        dataValues: data,
                        submitType: "json"
                     },
……….
……….
……….
</javascript>

And I rename my js like this : x.post.json.js

but json still undefined

Re: Extract dataObj values ???

yascorp — Wed, 30 Apr 2014 07:20:58 GMT

Yes, now It's working I have added requestContentType as a json, thank you so much Axel !!!
Best Regards