topic Re: How can I get the full path from a nodeRef ? in Alfresco Archive

How can I get the full path from a nodeRef ?

zengqingyi12 — Tue, 01 Mar 2011 13:05:06 GMT

I am using alfresco share 3.0. and I have the nodeRef of an object, how can I get the full path of the object ?I try to generate the path by myself, but I can not get the site name of the nodeReffull path:http://localhost:8080/share/page/site/Hello/documentlibrary#path=/2011/3/000I must know which s

Re: How can I get the full path from a nodeRef ?

xinyieric — Thu, 03 Mar 2011 01:04:58 GMT

hi

in my documentlibrary, the url is:http://localhost:8880/share/page/site/ds/documentlibrary
so i use "this.options.siteId" to get the site id
is that you need?

Re: How can I get the full path from a nodeRef ?

zladuric — Mon, 07 Mar 2011 09:22:27 GMT

You can access this through root scope objects.

For example, in freemarker you would use ${url.url} for a full url.

They're listed on wiki here, so check it out:
http://wiki.alfresco.com/wiki/Surf_Platform_-_Freemarker_Template_and_JavaScript_API

Re: How can I get the full path from a nodeRef ?

zengqingyi12 — Wed, 09 Mar 2011 04:18:46 GMT

But I only have a UUID, how can I get it's path and redirect to it ?

Re: How can I get the full path from a nodeRef ?

zladuric — Wed, 09 Mar 2011 09:13:40 GMT

Ah sorry, I've misread your question.

Well, for one, you can use nodeRef.parent to find out about its parent? And go up until the "Sites" reference?

There are probably better ways though, you better not listen to me

Re: How can I get the full path from a nodeRef ?

mikeh — Wed, 09 Mar 2011 09:22:02 GMT

It's not a trivial problem to solve. We have an internal* helper webscript which you could use if you're on V3.3 or newer (it was introduced with Rules support I believe).

It's in the alfresco.war, at /slingshot/doclib/node/{store_type}/{store_id}/{id}/location, i.e. use the usual client-side or web tier remote calls.

Your other, much easier, option is to navigate to the document-details page instead, which just takes a nodeRef argument.

Thanks,
Mike

(* internal webscripts are not public APIs and therefore not guaranteed to work between upgrades)

Re: How can I get the full path from a nodeRef ?

zengqingyi12 — Fri, 11 Mar 2011 02:21:00 GMT

OK, thanks, finally I use regular expression to capture the "Site" parameter, and generate the URL by myself, thanks