topic Re: Turning a qname path into a NodeRef, not by searching in Alfresco Archive

Turning a qname path into a NodeRef, not by searching

nickburch — Thu, 13 Sep 2012 15:15:17 GMT

I thought that one of the core services supported this, but I can't for the life of me find it… I have a qname based path, something like "/app:company_home/app:dictionary/app:email_templates", and I want to get the NodeRef of that. However, I don't want to use the SearchService to do that lookup, a

Re: Turning a qname path into a NodeRef, not by searching

afaust — Fri, 14 Sep 2012 07:10:37 GMT

Hello,

your qname path is essentially a XPath expression and you can use the SearchService to resolve XPath expressions without going to SOLR. The XPath query language in Alfresco is implemented directly on top of the DB / core services - no SOLR involved. So SearchService.selectNodes() is the way to go here.

Regards
Axel

Re: Turning a qname path into a NodeRef, not by searching

nicolasraoul — Wed, 05 Apr 2017 04:35:35 GMT

I just tried the XPath NodeLocatorService solution, it leads to race conditions:

Nodes that have been created recently are sometimes not found (about 30% of calls fail, in my tests).

So I switched to using serviceRegistry.getNodeLocatorService().getNode("xpath", null, params); to get the NodeRef of the folders that I know always exist (such as /app:company_home/app:shared), and then use serviceRegistry.getFileFolderService().resolveNamePath for everything below these nodes.

I would use resolveNamePath all the time if I could, but unfortunately it would fail on a Alfresco installed in Japanese, for instance, because "Shared" becomes "共有フォルダ" in a Japanese Alfresco (yes, the path is different).

If anyone has any better idea I would be glad to hear about it 🙂

Cheers!

Nicolas Raoul