topic Re: connect to an Alfresco webservice [solved] in Alfresco Archive

connect to an Alfresco webservice [solved]

thierensbart — Wed, 07 Oct 2009 08:02:08 GMT

Hi,it's my first time messing around with the Alfresco SDK and API.I tried executing the FirstWebServiceClient after modifying the webserviceclient.properties file.But when executing the first line of the code AuthenticationUtils.startSession("admin", "admin");,all I get is:Exception in thread "main

Re: connect to an Alfresco webservice [solved]

thierensbart — Wed, 07 Oct 2009 08:03:35 GMT

Little sidenote:

I'm using Alfresco 3.2 but my SDK version is 2.9B. Could this be the source of the problem?

I'm guessing it isn't…

Re: connect to an Alfresco webservice [solved]

anders_brink — Wed, 07 Oct 2009 12:01:41 GMT

I don't know if this applies to the programming language you are using (Java is it??), but in Powerbuilder that I am using I also had to add the service name to the location of the API.
So the same code

repository.location=http://192.168.10.238:8081/alfresco/api

would in my coding language be repository.location=http://192.168.10.238:8081/alfresco/api/AuthenticationService

I don't know if this will help you, at least I hope it won't do you any harm.

/Anders

Re: connect to an Alfresco webservice [solved]

thierensbart — Wed, 07 Oct 2009 12:25:40 GMT

I tried that already and it gives the exact same error.

I have also updated all the wsdl files in the AlfrescoRemote project from

<wsdl:service name="AuthenticationService">
      <wsdl:documentation>Provides simple authentication capability.</wsdl:documentation>
      <wsdlort binding="auth:AuthenticationServiceSoapBinding" name="AuthenticationService">
         <wsdlsoap:address location="http://localhost:8080/alfresco/api/AuthenticationService"/>
      </wsdlort>
   </wsdl:service>

<wsdl:service name="AuthenticationService">
      <wsdl:documentation>Provides simple authentication capability.</wsdl:documentation>
      <wsdlort binding="auth:AuthenticationServiceSoapBinding" name="AuthenticationService">
         <wsdlsoap:address location="http://192.168.10.238:8081/alfresco/api/AuthenticationService"/>
      </wsdlort>
   </wsdl:service>

But I still get the same error.

I used WCFStorm to check if the Webservice did actually exist.

When I enter http://192.168.10.238:8081/alfresco/api/AuthenticationService, it doesn't work.
When I select the local wsdl-file for authentication authentication-service.wsdl, it works perfectly and I can provide login-credentials and receive a ticket.

So the service does exist, I'm just wondering what has to be changed/configured in order to be able to call it from my Java-class.
I just followed the FirstWebserviceClient-example and changed their 'localhost:8080' to my 192.168.10.238:8081 and yet it doesn't work…

I'm getting frustrated

Re: connect to an Alfresco webservice [solved]

mrogers — Wed, 07 Oct 2009 16:08:13 GMT

Yes you do need to keep your SDK and Alfresco version together.

But - are you sure you are using the correct URL, in particular are you really running Alfresco on port 8081 rather than 8080.

Re: connect to an Alfresco webservice [solved]

thierensbart — Thu, 08 Oct 2009 07:03:27 GMT

I am.

The url seems right since I can connect to it from WCFStorm (a program to test services) and I can easily create a working service reference in .NET to it.

So it's just some configuration that's not correct. Too bad I don't have a clue where.

Re: connect to an Alfresco webservice [solved]

thierensbart — Thu, 08 Oct 2009 09:34:30 GMT

Little update:

If I just use Axis to connect to the webservice I can connect and get a response, but it crashes while deserializing the response.

08-Oct-2009 11:33:19 org.apache.axis.client.Call invoke
SEVERE: Exception:
org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
   at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
   at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
   at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
   at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
   at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345)
   at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
   at org.apache.axis.client.Call.invoke(Call.java:2467)
   at org.apache.axis.client.Call.invoke(Call.java:2366)
   at org.apache.axis.client.Call.invoke(Call.java:1812)
   at org.alfresco.sample.webservice.Test.main(Test.java:19)
AxisFault
 faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
 faultSubcode: 
 faultString: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
 faultActor: 
 faultNode: 
 faultDetail: 
   {http://xml.apache.org/axis/}stackTrace:org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
   at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
   at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
   at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
   at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
   at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345)
   at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
   at org.apache.axis.client.Call.invoke(Call.java:2467)
   at org.apache.axis.client.Call.invoke(Call.java:2366)
   at org.apache.axis.client.Call.invoke(Call.java:1812)
   at org.alfresco.sample.webservice.Test.main(Test.java:19)

   {http://xml.apache.org/axis/}hostname:laptop-bart

org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
   at org.apache.axis.AxisFault.makeFault(AxisFault.java:101)
   at org.apache.axis.client.Call.invoke(Call.java:2470)
   at org.apache.axis.client.Call.invoke(Call.java:2366)
   at org.apache.axis.client.Call.invoke(Call.java:1812)
   at org.alfresco.sample.webservice.Test.main(Test.java:19)
Caused by: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
   at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
   at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
   at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
   at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
   at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345)
   at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
   at org.apache.axis.client.Call.invoke(Call.java:2467)
   … 3 more‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Re: connect to an Alfresco webservice [solved]

joaotpd — Thu, 08 Oct 2009 11:30:45 GMT

Hi!

Based on this:
http://wiki.alfresco.com/wiki/IngresTutorial_Alfresco_Web_Service_API_for_Java#Open_and_close_sessions

If your server host is: 192.168.10.238 and your sever port is: 8081.
Try to add this line to your code before you start the session:

WebServiceFactory.setEndpointAddress("http://192.168.10.238:8081/alfresco/api");‍

then authenticate:

AuthenticationUtils.startSession("admin", server_password);‍

Hope it helps…

João Duarte