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    <title>topic Re: Importing files to upload in Alfresco Archive</title>
    <link>https://connect.hyland.com/t5/alfresco-archive/importing-files-to-upload/m-p/238780#M191910</link>
    <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;SPAN&gt;the only way i konw how to do this, is to use the servlet conext to get the real (filesystem) path of the file:&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;void myFunc(ServletContext context) {&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;&amp;nbsp;&amp;nbsp; //returns full path. Ex: C:\tomcat\5.5\webapps\myapp\ProjectFolder\TempFolde\test.jpg&lt;/SPAN&gt;&lt;BR /&gt;&lt;SPAN&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; String fullCanonicalPath = context.getRealPath("/ProjectFolder/TempFolder/test.jpg");&lt;/SPAN&gt;&lt;BR /&gt;&lt;SPAN&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; FileInputStream fis = new FileInputStream(fullCanonicalPath);&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;}&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;with getClassLoader().getResourceAsStream() you can only access files in the classpath.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;steffen&lt;/SPAN&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
    <pubDate>Thu, 01 Oct 2009 15:07:45 GMT</pubDate>
    <dc:creator>steffen</dc:creator>
    <dc:date>2009-10-01T15:07:45Z</dc:date>
    <item>
      <title>Importing files to upload</title>
      <link>https://connect.hyland.com/t5/alfresco-archive/importing-files-to-upload/m-p/238779#M191909</link>
      <description>Hi, can someone give me alternatives to upload files. I use just the following piece of code:// Open the file and convert to byte array&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; InputStream viewStream = newContentNode.getClass().getClassLoader().getResourceAsStream("test.jpg");&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; byte[] bytes = null;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;try &amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;</description>
      <pubDate>Thu, 01 Oct 2009 13:31:59 GMT</pubDate>
      <guid>https://connect.hyland.com/t5/alfresco-archive/importing-files-to-upload/m-p/238779#M191909</guid>
      <dc:creator>z3r0</dc:creator>
      <dc:date>2009-10-01T13:31:59Z</dc:date>
    </item>
    <item>
      <title>Re: Importing files to upload</title>
      <link>https://connect.hyland.com/t5/alfresco-archive/importing-files-to-upload/m-p/238780#M191910</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;SPAN&gt;the only way i konw how to do this, is to use the servlet conext to get the real (filesystem) path of the file:&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;void myFunc(ServletContext context) {&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;&amp;nbsp;&amp;nbsp; //returns full path. Ex: C:\tomcat\5.5\webapps\myapp\ProjectFolder\TempFolde\test.jpg&lt;/SPAN&gt;&lt;BR /&gt;&lt;SPAN&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; String fullCanonicalPath = context.getRealPath("/ProjectFolder/TempFolder/test.jpg");&lt;/SPAN&gt;&lt;BR /&gt;&lt;SPAN&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; FileInputStream fis = new FileInputStream(fullCanonicalPath);&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;}&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;with getClassLoader().getResourceAsStream() you can only access files in the classpath.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;steffen&lt;/SPAN&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Thu, 01 Oct 2009 15:07:45 GMT</pubDate>
      <guid>https://connect.hyland.com/t5/alfresco-archive/importing-files-to-upload/m-p/238780#M191910</guid>
      <dc:creator>steffen</dc:creator>
      <dc:date>2009-10-01T15:07:45Z</dc:date>
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