topic Re: Problem with contentService.write in Alfresco Archive

Problem with contentService.write

igdolmo — Wed, 22 Jul 2009 15:04:43 GMT

Hello guys. I am having some problems with this method. When i make:Content content = contentService.write(ref, Constants.PROP_CONTENT, aux, contentFormat);i get this exception:628791AxisFault faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.generalException faultSubcode: faultString:

Re: Problem with contentService.write

openpj — Thu, 23 Jul 2009 17:37:20 GMT

Are you using a real DBMS?
Usually this appears on Apache Derby or HSQL database settings.

Re: Problem with contentService.write

igdolmo — Fri, 24 Jul 2009 10:22:37 GMT

hello,

I´m using the mysql embedded database. in earlier version i did this operation easy, but with 3.2 i´m having problems.

Another issue, how can i get the real name of the file at disk. i.e. i have a file with uuid = 87564994-4b97-42e4-b629-b22d347b32c1 and at disk its name is: 11c4148e-2767-42b0-9e7d-8691ec9e20da.bin . i earlier versions the disk name was the same as the uuid, but now no. what can i do.

thanks

Re: Problem with contentService.write

shamabbas — Thu, 03 Sep 2009 04:36:07 GMT

Hi all and igdolmo,
Did you find the solution how to get the real name of the file on the disk? yes uuid in db is different and in disk is different I found it with by facing very much difficulty. But file index get store in alf_node_properties > string_value field and in disk with same index name so easily can find buttttttt as you asked can we get real file name on disk? if you got the solution then please help me out too.

Thanks in advance.

Sham

Re: Problem with contentService.write

igdolmo — Thu, 17 Sep 2009 07:00:37 GMT

to get the disk filename you have to get the contetn property.

Reference r = new Reference(STORE, uuid, null);
        Node[] a = repositoryService.get(new Predicate(new Reference[]{r}, STORE, null));
        for(int i=0;i<a[0].getProperties().length;i++){
            if(a[0].getProperties(i).getName().equalsIgnoreCase("{http://www.alfresco.org/model/content/1.0}content")){
                url=a[0].getProperties(i).getValue();
            }
        }‍‍‍‍‍‍‍

then if you want the file path you just have to get the substring from "//" till "|" and concat it to the repository path

Re: Problem with contentService.write

shamabbas — Thu, 17 Sep 2009 12:00:16 GMT

Hi igdolmo,
Thanks a lot for replying. I have already fixed this problem. And now my application is working perfectly.
Thanks once again.

Sham